JS1 Mathematics 3rd Term

Week 1: Revision of Number Base System

Convert 101010 to a number in base 2.
Solution: Use long division method

21010  
2505R0
2252R1
2126R0
263R0
231R1
215R1
27R1
23R1
21R1
20R1
    
Answer 1111110010

Week 2: Word problem in symbolic terms

Topic: Use of Equality Sign in Statements
Place the equality sign where appropriate. (Source: MM P141 Activity 13.2 Q (ii))
a) 17 + 7 – 5 ? (28 ÷ 7) + 5
Solution
Use BODMAS
i.e. 24 – 5 ? 4 + 15
Therefore, 19 = 19
Therefore, 17 + 7 – 5 = (28 ÷ 7) + 5

NEW! Exam Questions. Click on
SS2 Biology 2nd Term to get started.

b) 2 x 16 ? 3 x 10 + 2
Solution
Use BODMAS
i.e. 32 ? 30 + 2
Therefore, 32 = 32
Therefore, 2 x 16 = 3 x 10 + 2

Trending Post

Select a Category

Senior School e-Classes

Archives

SS One Subjects 1st Term

SS Two Subjects 1st Term

SS Three Subjects 1st Term

NTI PgDE Past Q & A

SS One Subjects 2nd Term

SS Two Subjects 2nd Term

SS Three Subjects 2nd Term

Textbooks and References

SS One Subjects 3rd Term

SS Two Subjects 3rd Term

SSCE Past Questions

TRCN Past Q & A

Youtube Videos

Advertisement

eLearning eClasses eLibrary Solar Energy Training Project Mngmt Solar Robotics

Layer 1
Login Categories
error: Content is protected !!