# JS1 Mathematics 3rd Term

## Week 1: Revision of Number Base System

Convert 101010 to a number in base 2.
Solution: Use long division method

 2 1010 Â Â 2 505 R 0 2 252 R 1 2 126 R 0 2 63 R 0 2 31 R 1 2 15 R 1 2 7 R 1 2 3 R 1 2 1 R 1 2 0 R 1 Â Â Â Â Answer 1111110010

## Week 2: Word problem in symbolic terms

Place the equality sign where appropriate. (Source: MM P141 Activity 13.2 Q (ii))
a) 17 + 7 â€“ 5 ? (28 Ã· 7) + 5
Solution
Use BODMAS
i.e. 24 â€“ 5 ? 4 + 15
Therefore, 19 = 19
Therefore, 17 + 7 â€“ 5 = (28 Ã·Â 7) + 5

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SS2 Biology 2nd Term to get started.

b) 2 x 16 ? 3 x 10 + 2
Solution
Use BODMAS
i.e. 32 ? 30 + 2
Therefore, 32 = 32
Therefore, 2 x 16 = 3 x 10 + 2

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